# Numpy element wise division not working as expected

From the docs, here is how element division works normally

``````a1 = np.array([8,12,14])
b1 = np.array([4,6,7])
a1/b1
array([2, 2, 2])
``````

Which works. I am trying the same thing, I think, on different arrays and it doesn’t. For two 3-dim vectors it is returning a 3×3 matrix. I even made sure their “shape is same” but no difference.

``````>> t
array([[  3.17021277e+00],
[  4.45795858e-15],
[  7.52842809e-01]])
>> s
array([  1.00000000e+00,   7.86202619e+02,   7.52842809e-01])
>> t/s
array([[  3.17021277e+00,   4.03231011e-03,   4.21098897e+00],
[  4.45795858e-15,   5.67024132e-18,   5.92149984e-15],
[  7.52842809e-01,   9.57568432e-04,   1.00000000e+00]])
t/s.T
array([[  3.17021277e+00,   4.03231011e-03,   4.21098897e+00],
[  4.45795858e-15,   5.67024132e-18,   5.92149984e-15],
[  7.52842809e-01,   9.57568432e-04,   1.00000000e+00]])
``````

This is because the shapes of your two arrays are
t.shape = (3,1) and s.shape=(3,). So the broadcasting rules apply: They state that if the two dimensions are equal, then do it element-wise, if they are not the same it will fail unless one of them is one, an this is where it becomes interesting: In this case the array with the dimension of one will iterate the operation over all elements of the other dimension.

I guess what you want to do would be

``````t[:,0] / s
``````

or

``````np.squeeze(t) / s
``````

Both of which will get rid of the empty first dimension in t. This really is not a bug it is a feature! because if you have two vectors and you want to do an operation between all elements you do exactly that:

``````a = np.arange(3)
b = np.arange(3)
``````

element-wise you can do now:

``````a*b = [0,1,4]
``````

If you would want to do have this operation performed between all elements you can insert these dimensions of size one like so:

``````a[np.newaxis,:] * b[:,np.newaxis]
``````

Try it out! It really is a convenient concept, although I do see how this is confusing at first.