# Microsecond accurate timestamp in python?

Is there a way to maintain microsecond accuracy when converting a Python datetime to a timestamp?

``````>>> import datetime
>>> d1 = datetime.datetime(2013,7,31,9,13,8,829)
>>> import time
>>> d1_ts = time.mktime(d1.timetuple())
>>> d1
datetime.datetime(2013, 7, 31, 9, 13, 8, 829)
>>> d1_ts
1375279988.0
>>> d1.fromtimestamp(d1_ts)
datetime.datetime(2013, 7, 31, 9, 13, 8)
``````

I lose that `.829` on the conversion. This is rather important, because I have start and end timestamps that I need to step through at set intervals (with sub-second steps) to gather data from some sensors.

Eventually it will be used in a function similar to this:

``````from scipy import arange
sample_time = 0.02
for i in arange(d1_ts, d2_ts, sample_time):
# do stuff
``````

With a `sample_time` that small, the mircoseconds are important.

``````import datetime as DT
d1 = DT.datetime(2013, 7, 31, 9, 13, 8, 829)
epoch = DT.datetime(1970, 1, 1)

print(d1.timestamp()) #  python3
# 1375276388.000829
print((d1 - epoch).total_seconds())  # python2
# 1375261988.000829
``````

Also note that if you are using NumPy 1.7 or newer, you could use np.datetime64:

``````In : x = np.datetime64(d1)

In : x.view('<i8')/1e6
Out: 1375261988.000829

In : x.astype('<i8').view('<M8[us]')
Out: numpy.datetime64('2013-07-31T05:13:08.000829-0400')

In : x.astype('<i8').view('<M8[us]') == x
Out: True
``````

Sinces the `np.datetime64` provides an easy way to convert from dates to 8-byte `ints`, they can be very convenient for doing arithmetic as `ints` and then converting to dates.